This slideshow will explain some of the things the coyote does. Basically, we put measurements to what the coyote's done and he's ten times more awesome than before because of it!
Thursday, October 27, 2011
WE ARE DONE!!! WOO HOO!!!!!!!!!!
We've worked the entire first quarter on Wile E. Coyote Physics.
Annnnnnnnnd......IT'S DONE!!! WHOOOOP!
This slideshow will explain some of the things the coyote does. Basically, we put measurements to what the coyote's done and he's ten times more awesome than before because of it!
This slideshow will explain some of the things the coyote does. Basically, we put measurements to what the coyote's done and he's ten times more awesome than before because of it!
Monday, October 17, 2011
Cartoon Confusion
The internet is full of equations, most of them end up being useless. I'm still working on figuring out the coyote running over air and 1 million mph is a little weird and was gathered from an unstable equation. Meaning, I made the equation up myself.
The last couple of weeks I took the weight of a basilisk, about 1.32 lbs, and divided 46 lbs, the approximate weight of an average coyote, by the basilisk weight to get 35 as the quotient. I multiplied the basilisk's water speed of 5.2 mph by 35 to get the approximate speed the coyote would need to run on water on his hind legs, 182 mph. The coyote has big feet like the basilisk does so I accepted that as something that would work. I divided out the surface tension from 182 mph. Surface tension of water at average temperature is 72.8 dynes, converted to pounds that's .000161862439 lbs of force to break surface tension of water. 182 divided by .000161862439 and got 1,124,411.575 mph as the speed it would take to run on air. That's a very unstable equation because I'm certainly not a mathematician, I'm not even particularly good at math.
So I'm basically trying to repeat the process but this time, compare the coyote to a long jumper to explain how the coyote makes it across a 70+ meter canyon to crash into the other side.
The coyote project is proving to be a lot more difficult than I thought it would be. Who knew trying to calculate the force on a falling cartoon character could be so complicated?
The last couple of weeks I took the weight of a basilisk, about 1.32 lbs, and divided 46 lbs, the approximate weight of an average coyote, by the basilisk weight to get 35 as the quotient. I multiplied the basilisk's water speed of 5.2 mph by 35 to get the approximate speed the coyote would need to run on water on his hind legs, 182 mph. The coyote has big feet like the basilisk does so I accepted that as something that would work. I divided out the surface tension from 182 mph. Surface tension of water at average temperature is 72.8 dynes, converted to pounds that's .000161862439 lbs of force to break surface tension of water. 182 divided by .000161862439 and got 1,124,411.575 mph as the speed it would take to run on air. That's a very unstable equation because I'm certainly not a mathematician, I'm not even particularly good at math.
So I'm basically trying to repeat the process but this time, compare the coyote to a long jumper to explain how the coyote makes it across a 70+ meter canyon to crash into the other side.
The coyote project is proving to be a lot more difficult than I thought it would be. Who knew trying to calculate the force on a falling cartoon character could be so complicated?
Subscribe to:
Posts (Atom)